# Animate Julia Sets

←Möbius Transformation of a Doyle Spiral | Orbit Trap Fractals→ |
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## Demonstration of a Julia set

## Generate two Julia sets

**Change the palette**

**Pick colouring**

## Animate along a circle through the two chosen Julia-set-points

## Definition of a Julia set

There is one Julia set for each complex number \(c\).

Given a complex number \(c\), pick a complex number \(z_0\) and use the recursive formula \[z_{n+1}=z_n^2+c.\]

If \( |z_n|\nrightarrow \infty \text{ as }n\rightarrow \infty \) then \(z_0\) belongs to the filled-in Julia set. The true Julia set is the boundary of this set.

If the chosen number \(c\) gives rise to a connected Julia set, then \(c\) belongs to the Mandelbrot set (see The Mandelbrot Set for more information). The Mandelbrot set can be defined as the set of all complex numbers such that the corresponding Julia sets are connected. To illustrate this, the Mandelbrot set is shown as a background image in the example at the top.

In this case the function is given by \(f(z)=z^2+c\); you can also use other rational functions. Another example is shown and explained at Newton Fractals.

## Generating filled-in and true Julia sets

When using the iterative function \(f(z)=z^2+c\) repeatedly, points will be generated along a so called
**forward orbit**. When generating a filled-in Julia set, the distance to the origin after
a maximum number of such iterations can be used to decide if a point belongs to the filled-in Julia
set. When generating a true Julia set, i.e. the boundary of the filled-in set, it's better to use a
so called **backwards orbit**. The backwards orbit is generated by using the inverse of \(f\) which is multi-valued.
When iterating backwards, you get two points in each step. If one of the points is chosen at random, it will take
many iterations to get a satisfactory image since the points are not evenly distributed. In the interactive example at
the top, another approach is used: by counting how many times each pixel is visited, in each step a point from a pixel with
the minimum number of visits is chosen.

When using backwards orbits, there are at most two points that will not end up at the Julia set. Those are the roots of the equation \(z=z^2+c\).

## The interactive examples

## References

jQuery Plugin used on this site for picking colours: Spectrum - The No Hassle jQuery Colorpicker